A. Segment AD is 5 and segment AE is 4
The first step to factorising this expression, is finding what is common in each term.
The GCF of 3, 2 and -4 is 1 therefore we will not have a coefficient of the outside terms.
Then we have st, su and sv
s is common in all of them therefore we can take out s.
So far we have s( )
Now for each term we must find what we multiply by s to reach it.
3st / s = 3t
2su / s = 2u
-4sv / s = -4v
Now just put these values inside the brackets.
s(3t + 2u - 4v)
Answer:
The image is so small for me (┬┬﹏┬┬)
Step-by-step explanation:
Answer: 15 yards
Step-by-step explanation:
From the question, we have been informed that the Steelers are on the Cowboys' fifteen-yard line. Using the place value mat to calculate how much farther Steelers need to travel to score a touchdown goes thus:
Since the play is 15 yards from the Cowboys end-zone, therefore Steelers need to travel 15 yards for them score a touchdown.
If all the sides are doubled, then the surface area
is multiplied by (2²) = 4 times as great.
That would be 320 m² .