Let's list the given information. The frictional force, denoted as Ff, is equal to 0.200 N. We have to find the normal force, denoted as Fn. The relationship between Ff and Fn is written as:
Ff = μFn
where μ is the coefficient of friction
If there is no given data for μ, we can't solve this problem. Suppose μ = 0.5, then the normal force would be:
Fn = Ff/μ = 0.2/0.5 = 0.4 N
We have that the absolute pressure at the <u>bottom</u> of the tank is mathematically given as
Pabs=209.21Kpa
<h3>Absolute Pressure at the
bottom of the <em>tank</em></h3>
Question Parameters:
A 3-m-diameter vertical <em>cylindrical </em>tank is filled
with water to a depth of 11 m.
Generally the equation for the Absolute Pressure is mathematically given as
Pabs=Patm+pgh
Therefore
Pabs=101.3e3+(1000*9.81*11)
Pabs=209.21Kpa
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