Hello
We know that when the fisherman casts his line, it will travel in a parabolic path, typical to that of a projectile's motion.
Whenever an object is in projectile motion, its velocity has two components, the x-component and y-component. The x component is usually constant with acceleration 0; however, as we know that the acceleration due to gravity acts on any object moving vertically. This will be our acceleration for the vertical component. Now, we apply the equation of motion for the vertical component of velocity:
v^2 = u^2 +2as; where v is the y-component final velocity, u is y-component of the initial velocity, s is the distance traveled and a is the acceleration.
Whenever an object attains "maximum height", its vertical velocity instantaneously becomes 0; therefore, v = 0.
a = -9.81 m/s^2 (negative sign because velocity is upwards while acceleration downwards)
s = 2.9 m as stated
Plugging the values into the equation, u (vertical component of initial velocity) works out to be:
7.54 m/s in the vertical direction.
The vertical component of the velocity is:
velocity * sin(angle with horizontal)
Thus, velocity =
7.54/sin(25)
= 17.8 m/s
Answer:
Explanation:
a ) speed of passenger = circumference / time
= 2π R / Time
= 2 x 3.14 x 50 / 60
= 5.23 m /s
b )
centrifugal force = m v² /R
= (882 /9.8 ) x 5.23² / 50
= 77.47 N
Apparent weight at the highest point
real weight - centrifugal force
= 882 - 77.47
= 804.53 N
Apparent weight at the lowest point
real weight + centrifugal force
= 882 +77.47
= 959.47 N
c ) if the passenger’s apparent weight at the highest point were zero
centrifugal force = weight
mv² /R = mg
v² = gR
= 9.8 X 50
v = 22.13 m /s
d )
apparent weight
mg - mv² / R
= 882 - (882 / 9.8 )x 22.13²/50
= 882 + 882
= 1764 N
=
Answer:1.89 m
Explanation:
Given
Block travels in first second
It is released from rest i.e. initial speed is zero (u=0)
using
where a=acceleration
here acceleration is the component of gravity on incline plane (say )
so
So distance traveled in
So distance traveled in is
The box is kept in motion at constant velocity by a force of F=99 N. Constant velocity means there is no acceleration, so the resultant of the forces acting on the box is zero. Apart from the force F pushing the box, there is only another force acting on it in the horizontal direction: the frictional force
which acts in the opposite direction of the motion, so in the opposite direction of F.
Therefore, since the resultant of the two forces must be zero,
so
The frictional force can be rewritten as
where
,
. Re-arranging, we can solve this equation to find
, the coefficient of dynamic friction:
Answer:
3.844 x 10 to the 5th power
Explanation: