Answer:
Explanation:
Let mass of cart be m₁ and m₂
m₁ + m₂ = 1.5 kg
At the time of release , their momentum will be conserved
m₁ v ₁ = m₂ v₂
m₁ v ₁ = (1.5 - m₁ ) x 2 v₁
m₁ = 3 - 2m₁
3m₁ = 3
m₁ = 1 kg
m₂ = .5 kg
Answer:
Explanation:
Consider two particles are initially at rest.
Therefore,
the kinetic energy of the particles is zero.
That initial K.E. = 0
The relative velocity with which both the particles are approaching each other is Δv and their reduced masses are
now, since both the masses have mass m
therefore,
= m/2
The final K.E. of the particles is
Distance between two particles is d and the gravitational potential energy between them is given by
By law of conservation of energy we have
Now plugging the values we get
This the required relation between G,m and d
Answer:
14.0 cm
Explanation:
Draw a free body diagram of the block. There are three forces: weight force mg pulling down, elastic force k∆L pulling down, and buoyancy ρVg pushing up.
Sum of forces in the y direction:
∑F = ma
ρVg − mg − k∆L = 0
(1000 kg/m³) (4.63 kg / 648 kg/m³) (9.8 m/s²) − (4.63 kg) (9.8 m/s²) − (176 N/m) ∆L = 0
∆L = 0.140 m
∆L = 14.0 cm
When lost fluid is not replaced adequately, dehydration can result.
Answer:
If Earth's diameter doubled but density was similar to the old Earth, the planet's <u>mass would go up and gravity would be twice as strong</u>. That would instantly make <u>tides twice as much as it was before.</u>
Explanation:
brainliest please