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Nonamiya [84]
3 years ago
10

HELP PLEASEEEEEEEEEEEE

Physics
1 answer:
Bond [772]3 years ago
4 0
The answer would be a
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A new planet has been discovered that has a mass one-sixth that of Earth and a radius that is six times that of Earth. Determine
Soloha48 [4]

Answer:

0.045 m/s²

Explanation:

Let the mass of Earth be 'M' and radius be 'R'.

Given:

Mass of the new planet (m) = one-sixth of Earth's mass = \frac{M}{6}

Radius of new planet (r) = 6 times Earth's radius = 6R

We know that, acceleration due to gravity of a planet of mass 'M' and radius 'R' is given as:

g=\dfrac{GM}{R^2}

Now, this is acceleration due to gravity on Earth.

Now, acceleration due to gravity of new planet is given as:

g_{new}=\dfrac{Gm}{r^2}\\\\g_{new}=\dfrac{G\times\frac{M}{6}}{(6R)^2}\\\\g_{new}=\dfrac{GM}{6\times 36R^2}\\\\g_{new}=\frac{1}{216}(\frac{GM}{R^2})=\frac{1}{216}\times g


Now, the value of 'g' on Earth is approximately 9.8 m/s². So,

g_{new}=\frac{9.8}{216}=0.045\ m/s^2

Therefore, the free fall acceleration on the surface of this planet is 0.045 m/s².

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4 years ago
How many phase changes does ice undergo when it changes to water vapor in the water cycle?
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Two.
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8 0
3 years ago
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