Answer:
43cm²
Step-by-step explanation:
let's first consider the area of a square.
the area is L² which means all sides are equal so we take the length times the breadth which is both equal because like we said all sides are equal.
so to find the side of the square using the area, we take the square root of both of the area.
and also
so we have the height of the triangle as 5cm and the base is 4.2cm.
now, from the triangle, since we have two sides and it's a right-angled, we can use Pythagoras' formula.
so the side 6.53cm is also the same side as the largest triangle. Since it's a square, all sides are equal. So we find the area of the largest triangle by using the formula
Area = L²
Area = 6.53²
Area = 42.6cm
the nearest cm square
Area = 43cm²
Answer:
A: The solution to this system is no viable because it results in fractional values of tickets
Step-by-step explanation:
Let number of adult, child, and senior tickets be x, y and z respectively.
Thus;
x + y + z = 12 - - - (eq 1)
she purchases 4 more child tickets than senior tickets.
Thus, y = z + 4
Thus:
x + (z + 4) + z = 12
x + 2z + 4 = 12
x + 2z = 8 - - - (eq 2)
Also, We are told that Adult tickets are $5 each, child tickets are $2 each, and senior tickets are $4 each. She spends a total of $38,
Thus;
5x + 2(z + 4) + 4z = 38
5x + 2z + 8 + 4z = 38
5x + 6z + 8 = 38
5x + 6z = 38 - 8
5x + 6z = 30
Divide through by 5 to get;
x + (6/5)z = 6 - - - (eq 3)
Subtract eq 2 from eq 1 to get;
2z - (6/5)z = 8 - 6
2z - (6/5)z = 2
Multiply through by 5 to get;
10z - 6z = 10
4z = 10
z = 2½
It's not possible to have a fractional value of a ticket and thus we can say that the solution is not viable.
Answer:
No Options
∠QOB=45º
Step-by-step explanation:
we have that: point O=Incenter, sides S, Q, R they form right angles with the point O, angle OBC = 15º and angle OCR=30º, find angle QOB
we know that the sum of all the internal angles of a triangle is 180º, so
α =180-30-15-90=45º and β = 180-90-α → β = 180-90-45 =45º,
Finally β=∠QOB=45º
A. -1 < x < = 39
B. <----------------------------^ *------------->
< ___-1___0___1__2__3__4___5___6____7____>
the dot above the 3 is open...the dot above the 6 is solid
