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Marrrta [24]
3 years ago
6

Charlie spends 3/4 hour exercising every morning. He spends 1/6 hour weight training and the rest of the time running on the tre

admill. What fraction of a hour does Charlie spend.
Mathematics
1 answer:
Svetlanka [38]3 years ago
5 0
He spends 45 minutes exercising 1/6 of an hour or 10 minutes of weight training and the rest of the time on the treadmill and that is 35 minutes or 7/12 of an hour. Hope this helped!
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Solving these quadratics for x using complete the square 3x^2-4x-1=0. Show your work.
UkoKoshka [18]
Answer: x = (sqrt(7) + 2)/3 and
x = ( – sqrt(7) + 2)/3

Explanation:

3x^2 - 4x - 1 = 0

Divide both sides by 3:

3x^2/3 - 4/3x - 1/3 = 0/3
x^2 - 4/3x - 1/3 = 0
x^2 - 4/3x = 1/3
x^2 - 4/3x + (2/3)^2 = 1/3 + (2/3)^2
(x - 2/3)^2 = 1/3 + 4/9
(x - 2/3)^2 = 7/9

Sqrt both sides:

x - 2/3 = sqrt (7/9)
x - 2/3 = |sqrt(7)/3|

Set x -2/3 = sqrt(7)/3

=> x = (sqrt(7) + 2)/3

Set x - 2/3 = - sqrt(7)/3

=> x = ( - sqrt(7) + 2)/3
6 0
3 years ago
Help me to do this question ​
zysi [14]

Answer:

c1) adjacent

c2) not adjacent

c3) adjacent

c4) not adjacent

c5) adjacent

c6) not adjacent

d1) 20°

Complement: 90° - 20° = 80°

Supplement: 180° - 20° = 160°

d2) 77°

Complement: 90° - 77° = 13°

Supplement: 180° - 77° = 103°

d3) 101°

Complement: doesn't have a complement.

Supplement: 180° - 101° = 79°

d4) 90°

Complement: 90° - 90° = 0°

Supplement: 180° - 90° = 90°

d5) 96°

Complement: doesn't have a complement

Supplement: 180° - 96° = 84°

d6) x

Complement: 90° - x

Supplement: 180° - x

d7) y

Complement: 90° - y

Supplement: 180° - y

7 0
3 years ago
Which equation represents a line which is parallel to the line x-8y=48 x−8y=48?
Daniel [21]
When the slopes of two lines are equal,they are parallel.
x - 8y = 48 \\  - 8y =  - 1x + 48 \\ y =  \frac{1}{8}x  + 6
so the equation of the parallel line to this one is :
y =  \frac{1}{8} x
hope this helps
3 0
3 years ago
Stacy saved 30% on a single item. If she saved $60.00, what was the cost of the item before the discount?
kifflom [539]
x-\ cost\ of\ item\\\\
30\%*x=60.00\\\\
0,3x=60.00\ \ \ |Divide\ by\ 0,3\\\\
x=200.00\\\\
Cost\ of\ item\ was\ equal\ to\ 200.00\$.

7 0
3 years ago
Find the sum of the geometric series 512+256+ . . .+4
mario62 [17]

\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}

\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}

so is the 8th term, then, let's find the Sum of the first 8 terms.

\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}

\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}}  \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}}  \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020

7 0
3 years ago
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