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Fudgin [204]
3 years ago
10

For fun: 17 + -3 - 3

Mathematics
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

11 or I'm just bad at math

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What is the mean of the data set?
olga nikolaevna [1]

Answer:

183

Step-by-step explanation:

125+141+213+155+281=915

915 divided by 5=183


3 0
4 years ago
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2. y = -2x² + 8x<br>Axis of Symmetry:<br>Vertex:<br>Domain:<br>Range:​
worty [1.4K]

Answer:

Part 1) The axis of symmetry is x=2

Part 2) The vertex is the point (2,8)

Part 3) The domain is all real numbers

Part 4) The range is all real numbers less than or equal to 8

Step-by-step explanation:

we have

y=-2x^{2}+8x

This is a vertical parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

step 1

Find the vertex

Convert the quadratic equation in vertex form

Factor -2 leading coefficient

y=-2(x^{2}-4x)

Complete the square

y=-2(x^{2}-4x+4)+8

rewrite as perfect squares

y=-2(x-2)^{2}+8

so

The vertex is the point (2,8)

step 2

Find the axis of Symmetry

we know that

In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex

the vertex is the point (2,8)

therefore

The axis of symmetry is x=2

step 3

Find the domain

The domain of the quadratic equation is the interval ------> (-∞,∞)

The domain is all real numbers

step 4

Find the range

The range of the quadratic equation is the interval ------> (-∞,8]

y\leq 8

The range is all real numbers less than or equal to 8

5 0
3 years ago
The sum of 11 and Matt’s savings is 51 use the variable m to represent Matt’s savings
weqwewe [10]

Answer:

40m

Step-by-step explanation:

6 0
3 years ago
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a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
Doss [256]

Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

Total time taken in 2003- total time taken in 2005

=2\frac{17}{24}-\frac{3}{8}

\frac{48+17}{24}-\frac{3}{8}

=\frac{65}{24}-\frac{3}{8}

=\frac{65-9}{24}

=\frac{56}{24}

\frac{7}{3}

=2\frac{1}{3} minutes


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4 years ago
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How is the graph of y= 1/3x related to its parent function y=1/x
V125BC [204]

B it is horizontally stretched by a factor of of 3 and reflected over the y

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3 years ago
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