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Tanya [424]
4 years ago
15

SUPER EASY QUESTION!!! HOW SMART ARE YOU? Which number has a 3 with a value that is 100 times greater than the value of the 3 in

20.342? Here are the answer choices choose wisely : 36.25 108.173 423.06 or 307.18
Mathematics
1 answer:
Alexus [3.1K]4 years ago
3 0

Answer:

36.25 ez I’m big brain

Step-by-step explanation:

You might be interested in
Last year the schools newspaper so if full page ad for $16.50 each of H half page is $9.60 each day school they plan to increase
erica [24]

Question isn't well formatted, however. From what can be gathered form the question :

Options are given

Answer:

4(1.5 * 16.50) + (1.5 * 9.60)

$113.40

Step-by-step explanation:

Last year:

Cost of full page ad = $16.50

Cost of half page ad = $9.60

50% increase in ad price this year :

Price, this year :

Full page = 1.50 * 16. 50 = $24.75

Half page = 1.50 * $9.60 = $14.4

Expression :

4(1.5 * 16.50) + (1.5 * 9.60)

Cost of a 4 and 1/2 page ad :

Full page = 4 * $24.75 = $99

Half page = 1 * $14.4 = $14.40

Total cost = $(99 + 14.40) = $113.40

8 0
3 years ago
In a clinical study of an allergy drug, 108 of the 200 subjects reported experiencing significant relief from their symptoms. Te
DochEvi [55]

Answer:

The decision is to not reject the null hypothesis.

At a significance level of 0.01, there is not enough evidence to support the claim that the proportion of all those using the drug that experience relief is significantly higher than 50% (P-value = 0.1443).

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that the proportion of all those using the drug that experience relief is significantly higher than 50%.

Then, the null and alternative hypothesis are:

H_0: \pi=0.5\\\\H_a:\pi>0.5

The significance level is 0.01.

The sample has a size n=200.

The sample proportion is p=0.54.

p=X/n=108/200=0.54

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.5*0.5}{200}}\\\\\\ \sigma_p=\sqrt{0.00125}=0.035

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.54-0.5-0.5/200}{0.035}=\dfrac{0.038}{0.035}=1.061

This test is a right-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z>1.061)=0.1443

As the P-value (0.1443) is greater than the significance level (0.01), the effect is  not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.01, there is not enough evidence to support the claim that the proportion of all those using the drug that experience relief is significantly higher than 50%.

6 0
4 years ago
15 Points and Brainliest :)
kodGreya [7K]

Answer:

Step-by-step explanation:

Hello, please consider the following.

Option A. First week we got $200.

Week 2, we got $200+$50=$250

Week 3, we got $250+$50=$300

Week 4, we got $300+$50=$350

Week 5, we got $350+$50=$400

Week 6, we got $400+$50=$450

\begin{array}{c |c |c |c |c |c |c|}Week & 1 & 2 & 3 & 4 & 5 & 6\\----&---&---&---&---&---&---\\Amount &200 &250 &300 &350 & 400 &450\end{array}

Option B. First week we got $200.

Week 2, we got $200+$200*10%=$200+$20=$220

Week 3, we got $220(1+10%)=$220(1.10)=$242

Week 4, we got $242(1.10)=$266.2

Week 5, we got $266.2(1.10)=$292.82

Week 6, we got $292.82(1.10)=$322.102

\begin{array}{c |c |c |c |c |c |c|}Week & 1 & 2 & 3 & 4 & 5 & 6\\----&---&---&---&---&---&---\\Amount &200 &220 &242 &266.2 & 292.82 &322.102\end{array}

Thank you.

6 0
3 years ago
What is the heat required in kilocalories to convert 2 kg of ice at 0°C completely into steam at 100°C?
Troyanec [42]
The total amount of heat is the sum of the heat required to convert the ice to water, raise the temperature of water from 0 to 100°, and convert the heated water to steam. The heats are the product of the mass and the specific heats.
  ice to water:   (2000 g) x 0.50 cal/g = 1000 cal
  raising of temp:  (2000 g) x 1 cal/g°C = 2000 cal
  water to steam:  (2000 g) x 0.48 cal/g = 960 cal
The total amount of heat is equal to 3960 calories or 3.96 kcal. 
6 0
3 years ago
A bag of Chocolates is labeled to contain 0.384 pounds of chocolate the actual weight of the chocolate is 0.3798 pounds. How muc
Daniel [21]

Answer:

<u>The actual weight is 1.1% less (100 - 98.9) than the labeled weight.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question properly:

Labeled weight of the bag of chocolates = 0.384 pounds

Actual weight of the bag of chocolates = 0.3798 pounds

2.  How much have you or lighter are the chocolates and the stated on the label. Show your reasoning.

Let's find how much we have comparing the labeled weight and the actual weight, using a Direct Rule of Three, this way:

Weight               Percentage

0.384                    100 %

0.3798                      x %

0.384x = 0.3798 * 100

0.384x = 37.98

x = 37.98/0.384

x = 98.9 (Rounding to one decimal place)

<u>The actual weight is 1.1% less (100 - 98.9) than the labeled weight.</u>

4 0
3 years ago
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