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Wewaii [24]
3 years ago
10

Which point lies on both y=5x−3 and y=−4x+6 ?

Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0
The answer is (1, 2)
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1546:12 =<br>Please pake cara​
defon

Answer:

It is a ratio. Is it?

If so, I think the answer is 773 : 6

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3 years ago
How is 3 millionths written in scientific notation
masya89 [10]
3,000,000 = 3<span> × 1,000,000 = </span>3<span> × 10</span>6<span>.</span>
7 0
3 years ago
Read 2 more answers
Find the length of side x simplest radical form with a rational denominator
Nuetrik [128]

Answer:

The length of x in the simplest radical form with a rational denominator will be:      

  •       x=\frac{5\sqrt{3}}{2}

Step-by-step explanation:

Given

hypotenuse = 5

angle Ф = 60°

To determine

x = ?

Using the trigonometric ratio

cos Ф = adjacent / hypotenuse

here

Ф = 60°

adjacent of 60° = x

hypotenuse = 5

so substituting Ф = 60°, adjacent = x and hypotenuse = 5 in the equation

cos Ф = adjacent / hypotenuse

so

cos\:60^{\circ }\:=\:\frac{x}{5}

       \frac{\sqrt{3}}{2}=\frac{x}{5}

switch sides

         \frac{x}{5}=\frac{\sqrt{3}}{2}

Multiply both sides by 5

         \frac{5x}{5}=\frac{5\sqrt{3}}{2}

Simplify

         x=\frac{5\sqrt{3}}{2}

Therefore, the length of x in the simplest radical form with a rational denominator will be:      

  •       x=\frac{5\sqrt{3}}{2}
5 0
3 years ago
A = ???? 4 −2
irinina [24]

Answer:

1. The matrix A isn't the inverse of matrix B.

2. |B|=12, |A|=12

Step-by-step explanation:

1. We want to know if matrix A is the inverse of matrix B, this means that if you do the product between B and A you have to obtain the identity matrix.

We have:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

and

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

A and B are 2×2 matrices (2 rows and 2 columns), if you multiply them you have to obtain a 2×2 matrix.

Then if A is the inverse of B:

B.A=I

Where,

I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

Observation:

If you have two matrices:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A.B=\left[\begin{array}{cc}(a.e+b.g)&(a.f+b.h)\\(c.e+d.g)&(c.f+d.h)\end{array}\right]

Now:

B.A=\left[\begin{array}{cc}3&2\\1&4\end{array}\right].\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}4.3+(-2).1&4.2+(-2).4\\(-1).3+3.1&(-1).2+3.4\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}12-2&8-8\\-3+3&-2+12\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]

B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]\neq \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=I\\\\\\B.A\neq I

Then, the matrix A isn't the inverse of matrix B.

2. If you have a matrix A:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant of the matrix is:

|A|=ad-bc

Then the determinant of B is:

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

a=3, b=2, c=1, d=4

|B|=3.4-2.1\\|B|=12-2=10

The determinant of A is:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

a=4, b=-2, c=-1, d=3

|A|=4.3-(-2).(-1)\\|B|=12-2=10

6 0
4 years ago
Answer this question. please​
dimaraw [331]

Answer:

\boxed{\textsf{ The total surface area of the cuboid is \textbf{62 cm} $\sf ^2$  .}}

Step-by-step explanation:

Given that the base area of the cuboid is 7cm² . And it's volume is 21cm³ . We need to find its total surface area . Now here we need to find the height . We can find height as ,

<u>Height</u><u> </u><u>:</u><u>-</u>

\qquad\boxed{\boxed{\sf Height =\dfrac{ Volume}{Area } }}

\sf\implies Height =\dfrac{Volume}{Area} \\\\\sf\implies h =\dfrac{ 21cm^3}{7cm^2}\\\\\implies \boxed{ \pink{\frak { Height = 3 cm.}}}

\rule{200}2

Let's find out the Total surface area .

<u>TSA </u><u>of </u><u>cuboid</u><u> </u><u>:</u><u>-</u><u> </u>

\qquad\boxed{\boxed{\sf TSA_{(cuboid)} =2(lb + bh + hl ) }}

<u>Put </u><u>on</u><u> the</u><u> respective</u><u> values</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies TSA_{(cuboid)}= 2( lb + bh + hl )\\\\\sf\implies TSA_{(cuboid)}= 2( 7cm\times 1cm + 1cm\times 3cm + 3cm \times 7 cm ) \\\\\sf\implies TSA_{(cuboid)}=2 ( 7cm ^2+3cm^2+21cm^2 ) \\\\\sf\implies TSA_{(cuboid)}=  2\times 31cm^2 \\\\\sf\implies \boxed{\pink{\frak{ TSA_{(cuboid)}=  62 cm^2}}}

3 0
3 years ago
Read 2 more answers
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