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Marrrta [24]
3 years ago
14

PLZ HELP I WILL MARK BRAINLIEST

Mathematics
2 answers:
mina [271]3 years ago
4 0

Answer:

Step-by-step explanation:

22 less than a number, q-22, ‘is’ 24 is =24

q-22=24 adding 22 to both sides gives q=46

dybincka [34]3 years ago
3 0

Answer:

q minus 22 = 24: Add 22 to both sides. The answer is 46.

Step-by-step explanation:

Solve each equation to see if it works.

Q - 22 = 24 does work.

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Answer:

First question: LCL = 522, UCL = 1000.5

Second question: A sample size no smaller than 418 is needed.

Step-by-step explanation:

First question:

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Upper bound:

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Second question:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The project manager believes that p will turn out to be approximately 0.11.

This means that \pi = 0.11

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The project manager wants to estimate the proportion to within 0.03

This means that the sample size needed is given by n, and n is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.11*0.89}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.11*0.89}

\sqrt{n} = \frac{1.96\sqrt{0.11*0.89}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.11*0.89}}{0.03})^2

n = 417.9

Rounding up

A sample size no smaller than 418 is needed.

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