B. Translated 10 units to the right, and 10 units down
Answer:
and
Step-by-step explanation:
The equation of the isotope decay is:
14-Carbon has a half-life of 5568 years, the time constant of the isotope is:
The decay time is:
(There is no a year 0 in chronology).
Lastly, the relative amount is estimated by direct substitution:
Answer:
B Domain: (-∞, ∞)
Range: (0,∞)
Step-by-step explanation:
Exponential functions are curves which approach a horizontal asymptote usually at y=0 or the x-axis unless a value has been added to it. If it has, the curve shifts. This function has addition on the exponent but not to the whole function so it does not change the asymptote. Its y - values remain between 0 and ∞. This is the range, the set of y values.
However, the range of exponentials can change based on the leading coefficient. If it is negative the graph flips upside down and its range goes to -∞. This doesn't have it either.
The addition to 1 on the exponent shifts the function to the left but doesn't change the range.
In exponential functions, the x values are usually not affected and all are included in the function. Even though it shifts, the domain doesn't change either. Its domain is (-∞, ∞).
Domain: (-∞, ∞)
Range: (0,∞)
The reduction from of the equation is .
<h2>
Given that</h2>
Reduce the equation; by .
<h3>According to the question</h3>
To reduce the given equation follow all the steps given below.
Reduce the equation; by .
To reduce the equation means we need to subtract one equation from another.
Then,
The reduction from the equation is,
Hence, the reduction from of the equation is .
To know more about Subtraction click the link is given below.
brainly.com/question/26182329
<u>Answer:</u>
P (S∩LC) = 0.03
<u>Step-by-step explanation:</u>
We are given that the probability that someone is a smoker is P(S)=0.19 and the probability that someone has lung cancer, given that they are a smoker is P(LC|S)=0.158.
Given the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).
P (LC|S) = P (S∩LC) / P (S)
Substituting the given values to get:
0.158 = P(S∩LC) / 0.19
P (S∩LC) = 0.158 × 0.19 = 0.03