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brilliants [131]
3 years ago
11

Write down the rules for multiplication and division of whole numbers​

Mathematics
1 answer:
MAXImum [283]3 years ago
8 0
As division is the inverse of multiplication, the rules for division are the same as the rules for multiplication. So when multiplying and dividing positive and negative numbers remember this: If the signs are the same the answer is positive, if the signs are different the answer is negative.
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Please help! I’ll mark you as brainliest
dezoksy [38]

Answer:

$37,449

Step-by-step explanation:

<u>First convert 5% into a decimal</u>

.05

<u>Multiply the decimal by Alice's salary</u>

$39,420(.05)=1,971

<u>Now we subtract that answer from her salary this year</u>

$39,420-1,971=$37,449

<h3><u>Alice's salary last year was $37,449</u></h3>
5 0
3 years ago
What are the 4 letters
sammy [17]

Answer:

BGHA

Step-by-step explanation:

You have to find all of the coordinates first in the order they are written:

(0,4)

(-4,3)

(2,0)

(0,-1)

Now use the code at the right to find the letters for each coordinate:

(0,4) B

(-4,3) G

(2,0) H

(0,-1) A

Now write it in this order (all caps): BGHA.

Hope it helps and is correct!

4 0
3 years ago
Read 2 more answers
F(x)=∣x∣
elixir [45]

Answer:

Step-by-step explanation:

There are two transformations, one vertical, one horizontal.

The + 9 part outside the absolute value sign moves the graph up 9 units.

Replacing  x  with  x - 1 moves the graph right 1 unit.

<em>Comment:</em>  The horizontal shifts sometimes appear backwards:  x - 1 looks like a shift to the left, but it's not.

Example:  f(4) = |4| = 4.  To get the same output (4) from g(x), you have to use a value for  x  that is 1 unit <u>larger</u> than 4.  g(5) = |5 - 1| = 4.

5 0
3 years ago
Jack likes to go fishing. While waiting for the fishes to bite, he formulates the following model for the process: fishes bite a
gogolik [260]

Answer:

a) 0.122

b) 3.35 × 10⁻⁴

c) 0.1071

Step-by-step explanation:

Here we have the Poisson process given by

P(N(t) = k) = \frac{e^{-\lambda t} (\lambda t)^k }{k!}

Where:

λ = Rate = 4 bites/hour and

t = Length of time that is

Mean = λt

Where k = 6 fishes bites and t = 2 hours we have

P(N(2) = 6) = \frac{e^{-4 \times 2} (4 \times 2)^6 }{6!} = 0.122

b) The probability that he fails to catch any fishes during the first two hours is the probability t that he catches 0 fish as follows

P(N(2) = 0) = \frac{e^{-4 \times 2} (4 \times 2)^0 }{0!} = 3.35 \times 10^{-4}

(c) Here we have

P(N(2) = 6) =  0.122

For 1 fish caught in two times we have first time no fish and second time he caches a fish gives

0.122×(1-0.122) = 0.1071

4 0
3 years ago
Solve algebraically <br> x-4y=-10<br> x+y=5
Ber [7]

Answer:

if x+y=5, then x=5-y

so x-4y=-10

5-y-4y=-10

5-5y=-10

-5y=-15

y=3

x=5-y

x=5-3

x=2

x=2; y=3

8 0
3 years ago
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