Answer:
Option d is correct = Negative ion
Explanation:
We know that an atom consist of electrons, protons and neutrons. Neutrons and protons are present inside the nucleus while electrons are present out side the nucleus. Electron has a negative charge and is written as e⁻. The mass of electron is 9.10938356×10⁻³¹ Kg
. While mass of proton and neutron is 1.672623×10⁻²⁷Kg and 1.674929×10⁻²⁷ Kg respectively.
Symbol of proton= P⁺
Symbol of neutron= n⁰
The number of electron or number of protons are called atomic number while mass number of an atom is sum of protons and neutrons. The umber of protons and electrons are always equal to make the atom electrically neutral and when an atom loses its valance electron the number of protons increases and thus positive charge increased and atom form cation.
When an atom gain electron negative charge increase because of more number of electron thus atom form negative ion or anion. For example,
Anion formation:
X + e⁻ → X⁻
Cation formation:
X → X⁺ + e⁻
Thus option d is correct option.
Answer:
43.2 moles of carbon dioxide are required and 421g of glucose could be produced
Explanation:
Based on the reaction:
6CO2 + 6H2O → C6H12O6 + 6O2
1 mole of glucose, C6H12O6, requires 6 moles of carbon dioxide. 7.2moles of glucose requires:
7.2mol C6H12O6 * (6mol CO2 / 1mol C6H12O6) =
<h3>43.2 moles of carbon dioxide are required</h3><h3 />
618g of CO2 -Molar mass: 44.01g/mol- are:
618g * (1mol / 44.01g) = 14.04moles CO2
Moles C6H12O6:
14.04moles CO2 * (1mol C6H12O6 / 6mol CO2) = 2.34moles C6H12O6
Mass glucose -Molar mass: 180.156g/mol-
2.34moles C6H12O6 * (180.156g / mol) =
<h3>421g of glucose could be produced</h3>
Answer:
How many grams are in 0.50 moles of h2so4?
We assume you are converting between moles H2SO4 and gram. You can view more details on each measurement unit: molecular weight of H2SO4 or grams This compound is also known as Sulfuric Acid. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles H2SO4, or 98.07848 grams.
Explanation:
Answer:
The isoelectric point is that the <u>pH </u>at which the compound is in an electronically neutral form.
For diss equations<u>, p</u>lease find them in the enclosed file.
The pIs of 2 amino acids:
- Glutamate: pI = 3,2
- Histidine: pI = 7,6
Explanation:
Formula for the pI calculation: pI = (pKa1 + pKa2)/2
Given 3 pKa :
- Acid glutamic with an acid sidechain:
Use the lower 2 pKas (corresponding with 2 -COOH groups)
pKa1 = 2,19; pKa2 = 4,25; so pI = 3,2
- Histidine with 2 amino groups:
Use the higher 2 pKas ( -COOH group and -NH= group)
pKa1 = 6; pKa2 = 9,17; so pI = 7,6
I think A, I might be wrong though sorry
