3 years ago

There is multiple questions here please help me

Mathematics

2 answers:

olasank [31]3 years ago

7 0

1. A
2. C
3. B
4. C
5. B

Colt1911 [192]3 years ago

4 0

1. a. Unique Solution

2. a. Unique Solution

3. b. No Solution

4. c. Infinitely Many Solutions

5. b. No Solution

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= (1/3) * 1000 meters
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OR
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On a coordinate plane, triangle A has points (negative 2, 0), (negative 6, 0), (negative 4, 4). Triangle A prime has points (1,

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4 years ago

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Given f(x) =17 -x2 what is the average rate of change in f(x) over the interval [1,5]

Artist 52 [7]

By definition the average rate of change is given by:
 $AVR = \frac{f(x2) - f(x1)}{x2-x1}$
We have the following function:
 $f(x) =17 - x^2$
We evaluate the function for the given interval:
For X = 1:
$f(1) =17 - 1^2$
$f(1) =17 - 1$
$f(1) =16$
For X = 5:
$f(5) =17 - 5^2$
$f(5) =17 - 25$
$f(5) =-8$
Then, replacing values we have:
$AVR = \frac{-8 - 16}{5-1}$
$AVR = \frac{-24}{4}$
$AVR = -6$
Answer:
the average rate of change in f(x) over the interval [1,5] is:
 $AVR = -6$

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4 years ago

What is the general form of the equation of a circle with center at (a, b) and radius of length m?. A. x2 + y2 − 2ax − 2by + (a2

drek231 [11]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{a}{ h},\stackrel{b}{ k})\qquad \qquad 
radius=\stackrel{m}{ r}
\\\\\\
\boxed{(x-a)^2+(y-b)^2=m^2}\\\\
-------------------------------\\\\
(x^2-2ax+a^2)+(y^2-2yb+b^2)=m^2
\\\\\\
x^2-2ax+a^2+y^2-2yb+b^2-m^2=0
\\\\\\
x^2+y^2-2ax-2yb+(a^2+b^2-m^2)=0$

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4 years ago