First move the constant to the right and change its sign to the opposite,
3m=1-4
Then calculate,
3m=-3
Then divide both sides of the equation by 3,
m=-1
So the answer is m=-1
The answer is D ) 96. It is the 16th multiple of 6.
If a number is divisible by 2 and 3, it is divisible by 6
(Or) you can directly divide the number by 6 and if you don't get any remainder then you can confirm that the particular number is a multiple of 6.
96 is an even number and hence obviously it is divisible by 296/3=32 and hence it is also divisible by 3
<span>Hence 96 is a multiple of 6.</span>
Answer:
option C will be the correct answer here
Let t and s represent the masses of 20% and 60% alloys respectively.
t+s=80, s=80-t
(0.2t+0.6s)/80=0.52 multiply both sides by 80
0.2t+0.6s=41.6, now using s=80-t in this equation gives us:
0.2t+0.6(80-t)=41.6 perform indicated multiplication on left side
0.2t+48-0.6t=41.6 combine like terms on left side
-0.4t+48=41.6 subtract 48 from both sides
-0.4t=-6.4 divide both sides by -0.4
t=16, since s=80-t
s=64
So 16kg of 20% alloy is mixed with 64kg of 60% allow to make 80kg of a 52% alloy.
