Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that 
74% of student are taking an English class
This means that 
70% of students are taking both
This means that 
Find the probability that a randomly selected student is taking a math class or an English class.
This is
, which is given by:

So

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Answer:
l.h.s.
seco√(1-sin²o). (here cos²o=1-sin²o)
sec0√cos²o
seco×coso
1/coso×coso
1
r.h.s.
Answer:
I believe that if the power went off you wouldnd see at all.
Step-by-step explanation:
Mirrors bend light to show the images of yourself and others that you see. not sure if im right but... hope it helps.