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BaLLatris [955]
3 years ago
11

Help PLEASE the question is below.

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0
1/2 is your answer have a good day
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Given P(A) = 0.74, P(B) = 0.6 and P(ANB) = 0.494, find the value of
OverLord2011 [107]

Step-by-step explanation: Since we have given, P(A) = 0.75 and P(A|B) =0.8 .

So, P(A∩B) = P(B|A)× P(A) = 0.8×0.75 =0.6 .

We have given P(B|A') = 0.6

P(A’∩B) = P(B|A')×P(A') = 0.6 × 0.25 = 0.15.

P(B) = P(A∩B) + P(A'∩B) = 0.6 + 0.15 = 0.75.

=> P(A|B) = (∩)()=0.60.75

P

(

A

∩

B

)

P

(

B

)

=

0.6

0.75

= 0.8 .

5 0
3 years ago
Solve for x. write integer or simplified fraction.<br><br>22/2 = x/3
ale4655 [162]
<h3>I'll teach you how to solve 22/2 = x/3</h3>

--------------------------------------------------

22/2 = x/3

Switch sides:

x/3 = 22/2

Divide the numbers 22/2:

x/3 = 11

Multiply both sides by 3:

x/3*3= 11*3

Simplify:

x=33

Your Answer Is x= 33

plz mark me as brainliest :)

5 0
3 years ago
What property of numbers is demonstrated in the equation (10 + 7) × 9 = (10 × 9) + (7 × 9)?
HACTEHA [7]

This is the distributive property because you are distributing the 9 into both terms of the parenthesis.

(10 + 7) x 9  = 10(9) + 7(9)

Answer: Distributive Property

6 0
3 years ago
Read 2 more answers
Pour connaitre la distance qui la separes dune ile armelle vise un arbre de deux endroit distant de 10m sur une berge elle a pri
QveST [7]

Répondre:

AI = 32,36 m

IE = 30,78 m

Explication étape par étape:

Utilisation de Pythagore:

Cosθ = adjacent / hypoténus

AI = hypoténus

θ = 72 °

Adjacent = 10 m

Cos 72 = 10 / AI

0,3090169 = 10 / AI

AI = 10 / 0,3090169

AI = 32,36 m

De la trigonométrie;

IE = opposé

Adjacent = 10m

Tanθ = opposé / adjacent

Tan 72 = IE / 10

IE = Tan 72 * 10

IE = 3,0776835 * 10

IE = 30,78 m

4 0
3 years ago
Does anyone know to solve this?
Aloiza [94]

Answer:

Step-by-step explanBecause many objects are not regularly shaped their volume cannot be determined using a volume formula. The volume of these objects can be found by water displacement. A volume of water sufficient to cover the object is placed in a graduated cylinder and the volume read. The object is added to the cylinder and the volume read again. The difference between the two volumes is the volume of the object. This method is demonstrated using the same battery used above.

ation:

7 0
3 years ago
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