You could buy 9 pounds without exceeding your 18 dollar limit. You would solve it buy dividing the 18 by 2 to get your answer
Answer:
0.1426 = 14.26% probability that at least one of the births results in a defect.
Step-by-step explanation:
For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability that a birth results in a defect is independent of any other birth. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).
This means that 
A local hospital randomly selects five births.
This means that 
What is the probability that at least one of the births results in a defect?
This is:

In which



0.1426 = 14.26% probability that at least one of the births results in a defect.
Is the equation written correctly?
Line HK is the line of intersection between pllanes AMKH and HKDY.
Consider all given options:
1. Line PB is the line of intersection between pllanes APBM and PBDY. Since planes APBM || HKDY and AMKH || PBDY, then lines PB and HK are parallel.
2. Line AM is the line of intersection between pllanes APBM and AMKH. Since planes APBM || HKDY and parallel planes are cut by plane AMKH, then lines AM and HK are parallel.
3. Line YD is the line of intersection between pllanes HKDY and AMKH. Since planes AMKH || PBDY and parallel planes are cut by plane HKDY, then lines YD and HK are parallel.
4. Lines HA and HK intersect each other at point H, thus they are not parallel.
5. Lines BM and HK are not parallel, because MB || DK and DK intersect HK at point K.
Answer: correct choices are A, B, C.