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Vanyuwa [196]
3 years ago
5

PLEASE HELP!!

Physics
1 answer:
eimsori [14]3 years ago
3 0

Answer:

The Dietary Guidelines for Americans (Dietary Guidelines) is the cornerstone for Federal nutrition programs and a go-to resource for health professionals nationwide. The Dietary Guidelines provides food-based recommendations to promote health, help prevent diet-related chronic diseases, and meet nutrient needs. As the MyPlate icon shows, the five food groups are Fruits, Vegetables, Grains, Protein Foods, and Dairy. The 2015-2020 Dietary Guidelines for Americans emphasizes the importance of an overall healthy eating pattern with all five groups as key building blocks, plus oils

Explanation:

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Even when the head is held erect, as in the figure below, its center of mass is not directly over the principal point of support
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We are asked to determine the force required by the neck muscle in order to keep the head in equilibrium. To do that we will add the torques produced by the muscle force and the weight of the head. We will use torque in the clockwise direction to be negative, therefore, we have:

\Sigma T=r_{M\perp}(F_M)-r_{W\perp}(W)

Since we want to determine the forces when the system is at equilibrium this means that the total sum of torque is zero:

r_{M\perp}(F_M)-r_{W\perp}(W)=0

Now, we solve for the force of the muscle. First, we add the torque of the weight to both sides:

r_{M\perp}(F_M)=r_{W\perp}(W)

Now, we divide by the distance of the muscle:

(F_M)=\frac{r_{W\perp}(W)}{r_{M\perp}}

Now, we substitute the values:

F_M=\frac{(2.4cm)(50N)}{5.1cm}

Now, we solve the operations:

F_M=23.53N

Therefore, the force exerted by the muscles is 23.53 Newtons.

Part B. To determine the force on the pivot we will add the forces we add the vertical forces:

\Sigma F_v=F_j-F_M-W

Since there is no vertical movement the sum of vertical forces is zero:

F_j-F_M-W=0

Now, we add the force of the muscle and the weight to both sides to solve for the force on the pivot:

F_j=F_M+W

Now, we plug in the values:

F_j=23.53N+50N

Solving the operations:

F_j=73.53N

Therefore, the force is 73.53 Newtons.

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