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3 years ago

Please help im struggling on this

Mathematics

1 answer:

Ksivusya [100]3 years ago

8 0

Answer:

It looks like you cut off part of the questions...

Step-by-step explanation:

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How do you solve 19=v-(-9)

leva [86]

V=10. You can solve this by using the rule of subtracting negative numbers, which means if you are subtracting a negative it is the same as adding a positive. So basically V + 9 = 19, making V equal 10.

5 0

3 years ago

Someone help me asap please

denis23 [38]

Step-by-step explanation:

1, vertical- axis intercept is the water at the beginning

3, she should have included the y-intercept and x-intercept of the linear function

7 0

4 years ago

Ice cream is being put into a cone at a rate of 4 cm3/s. The cone has a radius of 2 cm and a height of 8 cm.

almond37 [142]

Answer:

0.5052 cm per sec ( approx )

Step-by-step explanation:

∵ The volume of a cone is,

$V=\frac{1}{3}\pi (r)^2h$

Where,

r = radius,

h = height,

Here, r = 2 and h = 8,

Thus, the volume of the cone is,

$V=\frac{1}{3}\pi (2)^2 8=\frac{32\pi }{3}$

When the cone is half filled,

Volume would be,

$V_1=\frac{V}{2}=\frac{16\pi }{3}$

Now, $\frac{r}{h}=\frac{1}{4}\implies r=\frac{h}{4}$

$V_1=\frac{1}{3}\pi (\frac{h}{4})^2 h=\frac{\pi h^3}{48}----(1)$

$\implies \frac{\pi h^3}{48} = \frac{16\pi }{3}$

$\implies h \approx 6.35$

Differentiating equation (1) with respect to t ( time )

$\frac{dV_1}{dt}=\frac{\pi h^2}{16}\frac{dh}{dt}$

We have, $\frac{dV_1}{dt}=4\text{ cube cm per s},h=6.35\text{ cm}$

$4=\frac{\pi (6.35)^2}{16}\times \frac{dh}{dt}$

$\implies \frac{dh}{dt}=\frac{64}{6.35^2 \pi}\approx 0.5052\text{ cm per sec}$

7 0

3 years ago

PLEASE HELP !!! ILL GIVE BRAINLIEST!! *DONT SKIP* ILL GIVE 40 POINTS.

Delicious77 [7]

Answer:

-35 i think

Step-by-step explanation:

hope dis helps

4 0

3 years ago

What is the area of the triangle?<br> 24<br> 10<br> 26<br> units 2 HELP PLEASE

fgiga [73]

A=1/2x Base x Height

= 1/2 (10)(24)

=120

5 0

3 years ago

Please help im struggling on this ​

Please help im struggling on this