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3 years ago

PLEASE HELP, NO LINKS OR I WILL REPORT

Mathematics

2 answers:

LekaFEV [45]3 years ago

7 0

Answer: 94

Step-by-step explanation: :)

pychu [463]3 years ago

4 0

Answer: I belive it is

Step-by-step explanation:

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(Solve.) I have 1/10 of a pie left over. My sister and I plan to share it equally. What fraction of the pie will each of us get?

AleksAgata [21]

You would each get 1/20 of a pie.

Personally I think you should just buy another pie, because 1/20 is very little.

Explication:
Half of 1/10 is 1/20

4 0

3 years ago

Read 2 more answers

Find r, the common ratio.<br> {-252, 126, -63, 31.5, ...}

storchak [24]

Answer:

÷ -2

Step-by-step explanation:

8 0

3 years ago

Please help and shows workings of the attached screenshot

Ad libitum [116K]

Answer:

Hey, do you know how to screenshot images? There is also a website for Brainly if needed

Step-by-step explanation:

7 0

3 years ago

Find the GCF of the monomials 27x^2 and 81x^5.

Rudiy27

27x² and 81x⁵

81 = 27*3
x⁵ = x²x³

81x⁵ = 27*3*x²x³= (27x²)*3x³

We can see that 81x⁵=(27x²)*3x³ includes as a factor 27x²,
so GCF is 27x².

5 0

4 years ago

Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)

DENIUS [597]

Compute the necessary values/derivatives of $f(x)$ at $x=1$ :

$f(1)=3$

$f'(1)=2$

$f''(1)=-12$

$f'''(1)=-12$

$f^{(4)}(1)=48$

$f^{(5)}(1)=120$

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) $f(x)$ at $x=1$ by

$T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5$

$T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5$

###

Another way of doing this would be to solve for the coefficients $a,b,c,d,e,g$ in

$f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5$

by expanding the right hand side and matching up terms with the same power of $x$ .

5 0

3 years ago