The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three. Option B is correct.
<h3 /><h3>How do you calculate the volume of a cube?</h3>
Assume the side length of the cube under consideration is L units. The volume of the cube is then equal to L³ cubic units.
The volume of a cube is;
V = L³
Ubes have equal-length sides. The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three.
Hence option B is correct.
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Answer:
x = 1.58 m
, As this distance is much less than the distance to Ferdinand, it doesn't get wet
Explanation:
This problem can take a small amount of water as if it were a particular to analyze if it reaches where Ferdinand is (x = 10m), with this analysis we see that we can treat this problem as a projectile launch.
Let's look for the time it takes to reach the ground, the water initially comes out horizontally, so the initial vertical speed is zero (I go = 0)
y = t - ½ g t²
y = 0 - ½ g t²
t² = -2y / g
t² = - 2 (-1.0) /9.81
t = 0.452 s
with this time we calculate the horizontal distance traveled
x = v₀ₓ t
x = 3.5 0.452
x = 1.58 m
As this distance is much less than the distance to Ferdinand, it doesn't get wet
Answer:
The pressure inside the dropper is same as the atmospheric pressure when the rubber bulb is not pressed. ... But when we press the rubber bulb the pressure inside the dropper increases and hence the water flows out. Atmospheric pressure acting from outside the dropper balances the pressure exerted by water and water does not come out of a dropper. On pressing the dropper inside pressure of water becomes more than outside atmospheric pressure and water run out. When we press the bulb of a dropper with its nozzle kept in water, air in the dropper is seen to escape in the form of bubbles. Once we release the pressure on the bulb, water gets filled in the dropper.
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New force is 1/4 of force when distance is doubled
(a) time taken for the car to accelerate from v to 2v = t =
(b) velocity of the car moving at 2t seconds = ΔV = 2at
(a) we know that,
a=
where, is the final velocity
is the initial velocity
a = acceleration
t = time
Time taken to accelerate from V to 2V:
t =
(b) We know that,
a=
where, is the final velocity
is the initial velocity
a = acceleration
t = time
how fast is the car moving at 2t seconds after starting,
we can represent - = ΔV
at time = t= 2t, it becomes
a= = a = ΔV/2t
t= ΔV/2a
ΔV = 2at
<h3>What is acceleration?</h3>
Rate of change of velocity with time, both in terms of speed and direction is known as acceleration.
<h3>What is speed?</h3>
- the rate at which an object's location changes in any direction.
- The distance traveled in relation to the time it took to travel that distance is how speed is defined.
- Since speed simply has a direction and no magnitude, it is a scalar quantity.
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