Factorise 4a^2+b^2-4ab-8a+4b+4

Mathematics

1 answer:

Dima020 [189]3 years ago

6 0

Answer:

The factorized form of the given expression is $4 [(a-1)^2 - b(a - 1 + \frac{b}{4})]$

Step-by-step explanation:

Given;

4a² + b² - 4ab - 8a + 4b + 4

This expression is factorized as follows;

(4a² - 8a + 4) + (b² - 4ab + 4b)

(4a² - 4a - 4a + 4) + b² - 4b(a - 1)

(4a - 4)(a - 1) + b² - 4b(a - 1)

(4a - 4)(a - 1) - 4b(a - 1) + b²

4(a - 1)(a - 1) - 4b(a - 1) + b²

4(a - 1)² - 4b(a - 1 + b/4)

$4(a- 1)^2 - 4b(a - 1 + \frac{b}{4} )\\\\4 [(a-1)^2 - b(a - 1 + \frac{b}{4})]$

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