I am having trouble find the area

A) Addition

SCORPION-xisa [38]

Answer:

3+16 divided by 4 is 4.75

4×7-2×6..... is5.33

168

5 0

3 years ago

Suppose you have 3 quizzes and want an average of 7 points. List at least five ways this average can be accomplished. keep in mi

Sunny_sXe [5.5K]

Answer:

4,9,8 = 4+9+8 = 21

9,9,3 = 9+9+3 = 21

6,7,8 = 6+7+8 = 21

8,8,5 = 8+8+5 = 21

5,7,9 = 5+7+9 = 21

Step-by-step explanation:

The question says you get 7 points per quiz out of 3 quizzes.

7+7+7 = 21

Now that we know that we need a total score of 21, we therefore need to distribute it among the three quizzes.

Remember;

None of these scores are to be higher than 10. We need to add up scores below 10.

4,9,8 = 4+9+8 = 21

9,9,3 = 9+9+3 = 21

6,7,8 = 6+7+8 = 21

8,8,5 = 8+8+5 = 21

5,7,9 = 5+7+9 = 21

All of these gives 7 as average.

8 0

3 years ago

A theater group made appearances in two cities. The hotel charge before tax in the second city was $500 lower than in the first.

Mazyrski [523]

Answer:

First city: $5,500

Second city: $5,000

Step-by-step explanation:

Let's define x as the hotel price in the first city and y the hotel price in the second city. We can start with this equation:

y = x - 500 (The hotel before tax in the 2nd city was $500 lower than in the 1st.)

Then we can say

0.065x + 0.045y = 582.50 (the sum of the tax amounts were $582.50)

We place the value of y from the first equation in the second equation:

0.065x + 0.045 (x - 500) = 582.50

0.065x + 0.045x - 22.50 = 582.50 (simplifying and adding 22.5 on each side)...

0.11x = 605

x = 5,500

The cost of the first hotel was $5,500

Thus, the cost of the second hotel was $5,000 (x - 500)

6 0

3 years ago

The following information was obtained from matched samples. Individual Method 1 Method 2 1 7 5 2 5 9 3 6 8 4 7 7 5 5 6 Refer to

kykrilka [37]

Answer:

$p_v =2*P(t_{(8)}$

c. should not be rejected

Step-by-step explanation:

1) Data given and notation

The data given is:

Method 1 : 7,5,6,7,5

Method 2: 5,9,8,7,6

$\bar X_{1}=6$ represent the mean for the method 1

$\bar X_{2}=7$ represent the mean for the method 2

$s_{1}=1$ represent the sample standard deviation for the method 1

$s_{2}=1.58$ represent the sample standard deviation for the method 2

$n_{1}=5$ sample size selected for the Consultant A

$n_{2}=5$ sample size selected for the Consultant B

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the difference is equal to 0, the system of hypothesis would be:

Null hypothesis: $\mu_{1}- \mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{6-7}{\sqrt{\frac{1^2}{5}+\frac{1.58^2}{5}}}=-1.195$ (1)

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=5+5-2=8$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(8)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis. So the best option would be:

c. should not be rejected

3 0

3 years ago

Find the surface area of the prism!<br><br> The surface area is ___ in(2)

Blizzard [7]

Answer: 470 inches squared.

Step-by-step explanation: (15x8 + 15x5 + 8x5) x 2 = 470 inches squared

5 0

3 years ago

I am having trouble find the area​

I am having trouble find the area