F'(x) = 6x^2 - 18x + 12
= 6(x^2 - 3x + 2)
= 6(x - 2)(x - 1) = 0 at turning points
at turning points x = 1 and x = 2
f''(x) = 12x - 18
so when x = 1 f''(x) <0 (maximum) and when x = 2 f''(x) > 0 (minimum)
Answer:
Step-by-step explanation:
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Answer:
4 + x = 16
Step-by-step explanation:
In general, if we have an equation that has just one variable, such as x, then "solving the equation" means finding the set of all values that can be substituted for the one variable to produce a valid equation.
Isolate "x" on one side of the algebraic equation by adding the negative number that appears on the same side of the equation as the "x." For example, in the equation "x - 5 = 12", rewrite the equation as "x = 12 + 5" and solve for "x."
Based on the balance at the start of May and the purchases and payments made by Ruth, the balance at the beginning of April was b. $797.22.
<h3>What was the beginning balance in April?</h3><h3 />
First find the monthly rate:
= 10.91% / 12
= 0.909%
The beginning balance is x:
May balance = (Beginning balance x (1 + monthy rate) + Purchases - Payments
847.64 = x × 1.00909 + 88.34 - 45.17
1.00909x = 847.64 - 88.34 + 45.17
x = $797.22
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would this be considered rise over run?