Given six consecutive integers with a sum of seven times the
1 answer:
Answer:
<em>x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 + x + 6 = 7(x + 1)</em>
Step-by-step explanation:
<u>Equations</u>
The situation can be written as an algebraic equation by setting the variables as follows:
x = first integer
x + 1 = second integer
x + 2 = third integer
x + 3 = fourth integer
x + 4 = fifth integer
x + 5 = sixth (and last) integer
The sum of all six numbers must be equal to 7 times the second number, thus:
x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 + x + 6 = 7(x + 1)
You might be interested in
1/6 + 2/3=
1/6+4/6 being 6 the common denominator
5/6 which is in simplest form
Answer:
8
Step-by-step explanation:
Answer: 0.720
Step-by-step explanation:
0.720 = 18/25
0.51 = 51/100
0.144 = 18/125
0.023 = 23/1000
Formula C= 2(3.14)(R)
We are looking for R first, so
=
——
2
r= 25.12
————
2(3.14)
r= 25.12
———-
6.28
r= 4
diameter= r(2)
4(2)= 8
THE DIAMETER OF THE CIRCLE IS 8
Answer:
It goes the last option then the 2nd option the the first option.