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marusya05 [52]
3 years ago
8

Drag each tile to the correct box. Not all tiles will be used. Consider function f. ​

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

Steps in order will be

1. y=\sqrt{7x-21}\\2. y^2=7x-21 \\ 3. y^2=7(x-3)\\4. \frac{y^2}{7}=x-3\\ 5. x=\frac{y^2}{7}+3\\6.  f^{-1}(x)=\frac{1}{7}x^2+3 \:where\: x\geq 0

Step-by-step explanation:

Consider the function f(x)=\sqrt{7x-21}

We need to find f^{-1}(x)

For finding f^{-1}(x)  replace f(x) with y

Step 1: Replace f(x) with y

y=\sqrt{7x-21}

Now, solve for x

Step 2: Taking square on left side

y^2=(\sqrt{7x-21})^2\\y^2=7x-21

Step 3 : take 7 common

y^2=7(x-3)

Step 4 : Divide both sides by 7

\frac{y^2}{7}=x-3

Step 5: Add 3 on both sides

\frac{y^2}{7}+3=x-3+3\\x=\frac{y^2}{7}+3

Step 6: Replace x with y and x with f^{-1}(x)

f^{-1}(x)=\frac{1}{7}x^2+3 where x≥0

Steps in order will be

1. y=\sqrt{7x-21}\\2. y^2=7x-21 \\ 3. y^2=7(x-3)\\4. \frac{y^2}{7}=x-3\\ 5. x=\frac{y^2}{7}+3\\6.  f^{-1}(x)=\frac{1}{7}x^2+3 \:where\: x\geq 0

Assuming one or 2 steps are missing in the diagram given.

cupoosta [38]3 years ago
5 0

Answer:

1. y=√7x-21

2. x=√7x-21

3. x^2 = 7y -21

4. x^2+21= 7y

5. 1/7x^2+3=y

6. 1/7x^2 + 3 = f^-1(x), where x≥0

Step-by-step explanation:

just got it correct on the test

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The order of x in both the numerator and the denominator are now both (1/2). Hence, dividing both the numerator and the denominator by x^{(1/2)} (same as \sqrt{x}) would ensure that all but the constant terms would approach 0 under this limit:

\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x} / \sqrt{x}}{(\sqrt{x + 1} / \sqrt{x}) + (\sqrt{x} / \sqrt{x})} \\ &= \lim\limits_{x \to \infty}\frac{1}{\sqrt{(x / x) + (1 / x)} + 1} \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1}\end{aligned}.

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