Answer:
substance A is water and substance B is chlorophyll
Explanation:
Answer:
If you heat a gas you give the molecules more energy so they move faster.
Explanation:
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Answer:
12.9 L Kr
General Formulas and Concepts:
<u>Chemistry - Gas Laws</u>
- Using Dimensional Analysis
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Explanation:
<u>Step 1: Define</u>
0.575 mol Kr
<u>Step 2: Identify Conversions</u>
1 mol= 22.4 L at STP
<u>Step 3: Convert</u>
<u /> = 12.88 L Kr
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
12.88 L Kr ≈ 12.9 L Kr