All categories

3 years ago

Elimination process 7a-3b = 26 a + 2b =11

Mathematics

1 answer:

VMariaS [17]3 years ago

5 0

Answer:(a=5,b=3)

7a-3b = 26--------(1)

a + 2b =11---------(2)

on mutlplying by7 in eq 2

= 7a+14b=77-------(3)

from eq(1) and (3) (on substracting)

7a+14b=77

7a-3b=26

________

=-17b=51

b=51/17

b=3

on putting value of b in eq 1

7a-3b = 26

=7a-9=26

7a=35

a=5

Step-by-step explanation:

hope it helps

mark me brainliest

You might be interested in

Help will give Brainly points

atroni [7]

The answer is B there you go have a nice day

5 0

3 years ago

3m=2(4+x) solve for x

algol13

Simple.........

3m=2(4+x)

Simplify...

3m=2(4+x)

3m=8+2x

Isolate the variable....

3m=8+2x
-8 -8

3m-8=2x

$\frac{3m-8}{2} = \frac{2x}{2}$

$\frac{3m}{2} -4=x$

Thus, your answer.

4 0

3 years ago

Read 2 more answers

A greater number than -8

sertanlavr [38]

Practically anything above -8
Such as -7, 2, 15600, anything not under -7.9

6 0

3 years ago

-2a3 - 3a2 + 4a + 6, 2a3 + 5a2 + 7 <br> sum the expression

zavuch27 [327]

Answer:

2a2 + 4a + 7

Step-by-step explanation:

As, - (2a3 - 3a2 + 4a + 6) + (2a3 + 5a2 + 7)

= 2a2 + 4a + 13

5 0

3 years ago

A rectangle has an area of 19.38 cm2. When both the length and width of the rectangle are increased by 1.50 cm, the area of the

Lostsunrise [7]

Answer: $5.7\ cm$

Step-by-step explanation:

Given

Rectangle has an area of $19.38\ cm^2$

Suppose rectangle length and width are $l$ and $w$

If each side is increased by $1.50\ cm$

Area becomes $A_2=35.28\ cm^2$

We can write

$\Rightarrow lw=19.38\quad \ldots(i)\\\\\Rightarrow (l+1.5)(w+1.5)=35.28\\\Rightarrow lw+1.5(l+w)+1.5^2=35.28\\\text{use (i) for}\ lw\\\Rightarrow 19.38+1.5(l+w)=35.28-2.25\\\Rightarrow l+w=9.1\quad \ldots(ii)$

Substitute the value of width from (ii) in equation (i)

$\Rightarrow l(9.1-l)=19.38\\\Rightarrow l^2-9.1l+19.38=0\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{(-9.1)^2-4(1)(19.38)}}{2\times 1}\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{5.29}}{2}\\\\\Rightarrow l=\dfrac{9.1\pm2.3}{2}\\\\\Rightarrow l=3.4,\ 5.7$

Width corresponding to these lengths

$w=5.7,\ 3.4$

Therfore, we can write the length of the longer side is $5.7\ cm$

8 0

3 years ago