This question is incomplete.Here is complete one
Consider a telescope with a small circular aperture of diameter 2.0 centimeters.
If two point sources of light are being imaged by this telescope, what is the maximum wavelength (lambda) at which the two can be resolved if their angular separation is 3.0x10^-5 radians? Express your answer in nanometers
Answer:
λ =492nm
Explanation:
Given Data
diameter=2.0 cm
angular separation=3.0x10^-5 radians
λ=?
Solution
sin(theta) = 1.22 x λ /D
λ=(0.02×sin(3.0×10⁻⁵))/1.22
λ=492nm
Answer:
0.29D
Explanation:
Given that
F = G M m / r2
F = GM(6m) / (D-r)2
G Mm/r2 = GM(6m) / (D-r)2
1/r2 = 6 / (D-r)2
r = D / (Ö6 + 1)
r = 0.29 D
See diagram in attached file
Answer:
It is A.Heat is transmitted and light is reflected.
Explanation:
It is given that,
Distance between the slits, d = 5 mm = 0.005 m
Distance between slit and screen, D = 1.4 m
For m = 2, and
For m = 2, and
Separation between two fringes is :
Hence, this is the required solution.