From gas equations
PV/T = Constant
Then
P1V1/T1 = P2V2/T2, but V1 = V2
Therefore,
P1/T1 = P2/T2
P2 = (P1T2)/T1
P1 = 40 psi
T1 = 60°F = 288.706 K
T2 = 90°F = 305.372 K
Substituting;
P2 = (40*305.372)/288.706 = 42.31 psi
Then, gauge pressure would read 42.31 psi.
Answer:
Force on front axle = 6392.85 N
Force on rear axle = 8616.45 N
Explanation:
As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels
Now we know that
now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle
so we can write torque balance about its center of mass
now from above equation
now we have
now the other force is given as
Answer:
total current =0.06A
Explanation:
The total resistance of Resistors connected in series is given as
Rs = R1 + R2 + R3....
Here, we have that two resistors are connected in series
therefore,
Rs = 100 + 100 = 200 Ω
But current according to ohm's law is given as
I= V/R
where I= current in ampere, A
V= Voltage in volts, V and
R= Resistance, in ohms,Ω
therefore,
I= V/Rs
I = 12/ 200 = 0.06 A
The distance travelled by the car after the first four hours of the trip is 370 km and the average speed for the first four hours of the trip is 92.5 kmph
v ( t ) = d ( t ) / t
v ( t ) = Velocity with respect to time
d ( t ) = Distance with respect to time
t = Time
For the first four hours, the following details are taken from the graph shown.
d ( 4 ) = 370 km
t = 4 hr
v ( 4 ) = 370 / 4
v ( 4 ) = 92.5 kmph
Average velocity can also be calculated using the formula V = ( u + v ) / 2 if the initial and final velocities are given. u represents initial velocity and v represents the final velocity.
Therefore,
Distance travelled in first 4 hours = 370 km
Average speed in first four hours = 92.5 kmph
To know more about average velocity
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