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ollegr [7]
4 years ago
10

Argue whether this chemical reaction supports or does not support the Law of Conservation of Matter.

Chemistry
1 answer:
Anit [1.1K]4 years ago
4 0

Explanation:

The reaction is as follows:

2Mg(s) + O2(g) ---> 2MgO(s)

and the researcher said that 32 g of MgO was produced.

Stoichiometry:

28 g Mg × (1 mol Mg/24.305 g Mg) = 1.15 mol Mg

15 g O2 × (1 mol O2/15.999 g O2) = 0.938 mol O2

1.15 mol Mg × (2 mol MgO/2 mol MgO) = 1.15 mol MgO

1.15 mol MgO × (40.3044 g MgO/1 mol MgO) = 46.6 g MgO

0.938 mol O2 × (2 mol MgO/1 mol O2) = 1.88 mol MgO

1.88 mol MgO × (40.3044 g MgO/1 mol MgO = 75.6 g MgO

Based on these numbers, the amount of product after the reaction is much less than expected so these results don't seem to support the law of conservation of matter.

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How many moles of water are produced when 24.3 ml of 0.100 m naoh is mixed with 31.4 ml of 0.08 m acetic acid?
slega [8]
<h3><u>Answer;</u></h3>

0.002512 moles of H2O

<h3><u>Explanation</u>;</h3>

The reaction between acetic acid ( CH3COOH) and NaOH is given by the equation;

CH3COOH + NaOH ------> CH3COONa + H2O

Number of moles of CH3COOH = molarity × volume in litres

                                                     = 0.08 × 31.4/1000

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Similarly number of moles of NaOH = 1 × 24.3/1000

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From the reaction the mole ratio of CH3COOH : NaOH

Therefore; 0.0243 moles of NaOH will react with 0.0243 moles of CH3COOH but no.of moles of CH3COOH given in the question are 0.002512  moles, which is less than what is required.

Thus; CH3COOH is the limiting reagent and amount of products produced will depend on amount of CH3COOH only.

Since; 1 mole of CH3COOH gives 1 mole of water.

Then; 0.002512 moles of CH3COOH will give 0.002512 moles of H2O

5 0
3 years ago
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yes


is


the


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7 0
3 years ago
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