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yan [13]
3 years ago
13

Solve for x. 5(x – 10) = 30 – 15x

Mathematics
1 answer:
Bad White [126]3 years ago
8 0

Answer:

x=4

Steps:

1. Distribute

2. Rearrange terms

3. Add  50 to both sides

4. Simplify

5. Add Add 15 to both sides of the equation

6. Simplify

7. Divide both sides of the equation by the same term

8. Simplify

5(x–10)=30–15x

5x-50=30-15x

5x-50=-15x+30

5x-50+50=-15x+30+50

5x=-15x+80

5x+15x=-15x+80+15x

20x=80

20x÷20=80÷20

x=4

I really hope this helps :)

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Given that the first term is LaTeX: t_1=5t 1 = 5, and the recursive definition is LaTeX: t_{n+1}=3\cdot t_nt n + 1 = 3 ⋅ t n, wh
Tamiku [17]

Answer:

  • <u>Fourth choice: 15</u>

Explanation:

The question is: given that the first term is    t_1=5    and the recursive definition is    t_{n+1}=3\cdot t_n    , what would be the second term (i.e.    t_2    )

A recursive defintion or recursive formula is an equation (a rule) that you apply over a term to find the next term, and so you can use it repeatedly to find the successive terms of a series.

In this case, your rule is that you multiply each term by 3, starting from 5.

Thus:

  • First term:     t_1=5

  • Second term = 3 × first term :    t_2=3\cdot t_1=3\cdot 5=15

Hence, your answer is 15 (the fourth choice).

3 0
3 years ago
Choose the methods of solving quadratic equations
atroni [7]

Answer:

Factoring square root method quadratic formula completing the square method . x1=3+(check)3 and x2=3-(check)3 .

Step-by-step explanation:

Have an amazing day<3 thirty percent chance this is right 70 it’s wrong

6 0
3 years ago
Blue ribbon 43 1/8in red ribbon 39 3/4in how much longer is the blue ribbon?
pantera1 [17]

43 1/8 - 39 3/4

43 - 39 = 4

1/8 - 3/4 = 1/8 - 6/8

= -5/8

4 - 5/8 = 3 3/8   answer


8 0
3 years ago
Suppose you want to count the number of​ four-letter passwords that can be formed using the letters in the word NUMBER. The four
WITCHER [35]

Answer:

D.The password must not follow order matter

Step-by-step explanation:

We are given that suppose you want to count the number of four letters password that can be formed using the letters in the word NUMBER.

We are given that all letters in the password must be all different .There is no nothing saying about order so we can make combination without order .

We have to find the number of 4- letter password that can be formed using letters in the word NUMBER.

By using Permutation formula we find the number of 4- letters password that can be formed by using the letters N,M,B,U,E,R.

Permutation formula : The number of arrangements when taken r objects at a time out of n objects

=\frac{n!}{(n-r)!}

Total letters in word NUMBER=N,U,M,B,E,R=6

n=6,r=4

Therefore, the number of arrangements  can be made from 6 letters when 4 letters taken at a time =\frac{6!}{(6-4)!}

The number of selection can be made from 6 letters when 4 letters taken at a time =\frac{6!}{(6-4)!}

The number of selection can be made from 6 letters when 4 letters taken at a time =\frac{6\times5\times 4\times3 \times 2!}{ 2!}

n!=n(n-1)(n-2)(n-3)...........3\cdot.2\cdot.1

The number of selection can be made from 6 letters when 4 letters taken at a time =360

Option D is correct.

Answer : D.The password must not follow order matter

6 0
4 years ago
CAN SOMEONE HELP
rusak2 [61]
The two triangles are similar triangles. 
The smaller triangle has hypotenuse 6 and a horizontal leg of 4
The large triangle has hypotenuse 6+12=18 and a horizontal leg of x, where x is some number larger than 4

Because the triangles are similar, we can form the proportion below and solve for x
x/4 = 18/6
6*x = 4*18
6*x = 72
6*x/6 = 72/6
x = 12

Final Answer: 12

6 0
4 years ago
Read 2 more answers
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