The correct answer, is Option C, I hope this helps :)
Answer:
The distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.
Explanation:
Given that
q₁ = 5 μ C
q₂ = - 4 μ C
The distance between charges = 50 cm
d= 50 cm
Lets take at distance x from the charge μ C ,the electrical field is zero.
That is why the distance from the charge - 4 μ C = 50 - x cm
We know that ,electric field is given as
Therefore the distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.
A)
R1 = 30/(7*60)
We are multiplying 7 with 60 because there are 60 seconds in 1 minute.
R1 = 30/420 = 0.0714 gallons/second
b) For this we need to express gallons to cubic meters.
1 gallon = 0.003785 m^3
R2 = 0.0714*0.003785 = 0.00027 m^3/s
c) V = R2*t where V is volume of some tank.
which means that
t=V/R2
t = 3698.8s or
t = 1.0274 hours
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