The top of the trajectory is the point where it changes from rising to falling. At that exact instant, its vertical speed is zero.
Answer:
The electron is 5.88 m far from origin when it momentarily stops.
Explanation:
The position of electron on x-axis is given by the equation:
x = 16 t m __________ eqn(1)
The speed of particle can be found out by taking derivative of "x" with respect to "t"
V = dx/dt = 16[-t + ]
V = 16(1 - t)
Now, when the electron stops, its velocity becomes zero.
V = 0 = 16(1 - t)
(1 - t) = 0
<u>Either</u>: = 0
-t = ln(0)
t = infinity (Since, time can not be infinite, thus this answer is rejected)
<u>Or</u>: 1 - t = 0
<u>t = 1 sec</u>
Therefore, at t= 1 sec, the electron will stop momentarily.
Using t = 1 sec in eqn (1), we find the position of electron.
x = 16(1) m
<u>x = 5.88 m</u>
<u></u>
<u>Mass Movement</u> is the best answer.
Answer:
- The x-component of the velocity of the third particle is
- The y-component of the velocity of the third particle is
- The increase in kinetic energy is
Explanation:
We can take conservation of linear momentum to find the velocities:
The initial momentum of the nucleus will be:
as is at rest.
After the decay, the first particle has a momentum
the second one has a momentum
By conservation of linear momentum we have:
for the third particle, we know that mass is conserved:
The velocity will be:
The kinetic energy is given by
And, as the initial kinetic energy is zero, this must be the increase in energy.