Answer:
T1 = 417.48N
T2 = 361.54N
T3 = 208.74N
Explanation:
Using the sin rule to fine the tension in the strings;
Given
amass = 42.6kg
Weight = 42.6 * 9.8 = 417.48N
The third angle will be 180-(60+30)= 90 degrees
Using the sine rule
W/Sin 90 = T3/sin 30 = T2/sin 60
Get T3;
W/Sin 90 = T3/sin 30
417.48/1 = T3/sin30
T3 = 417.48sin30
T3 = 417.48(0.5)
T3 = 208.74N
Also;
W/sin90 = T2/sin 60
417.48/1 = T2/sin60
T2 = 417.48sin60
T2 = 417.48(0.8660)
T2 = 361.54N
The Tension T1 = Weight of the object = 417.48N
Answer:
(a) Final speed of block = 3.2896 m/s
(b) 6.7350 m/s is the speed of the bullet-block center of mass?
Explanation:
Given that:
Mass of bullet (m₁) = 6.20 g
Initial Speed of bullet (u₁) = 929 m/s
Final speed of bullet (v₁) = 478 m/s
Mass of wooden block (m₂) = 850g
Initial speed of block initial (u₂) = 0 m/s
Final speed of block (v₂) = ?
<u>By the law of conservation of momentum as:</u>
<u>m₁×u₁ + m₂×u₂ = m₁×v₁ + m₂×v₂</u>
6.20×929 + 850×0 = 6.20×478 + 850×v₂
Solving for v₂, we get:
<u>v₂ = 3.2896 m/s</u>
Let the V be the speed of the bullet-block center of mass. So,
V = [m₁* u₁]/[m₁ + m₂] (p before collision = p after collision)
= [6.2 *929]/[5.2+850]
<u>V = 6.7350 m/s
</u>
Answer:
3.1 × 10^- 7 m and 2.1 × 10^-7 m
Explanation:
First we must convert each value of energy to Joules by multiplying its value by 1.6 ×10^-19. After that, we can now obtain the wavelength from E= hc/λ
Where;
h= planks constant
c= speed of light
λ= wavelength of light
For 6.0ev;
E= 6.0 × 1.6 ×10^-19
E= 9.6 × 10^-19 J
From
E= hc/λ
λ= hc/E
λ= 6.6 × 10^-34 × 3 × 10^8/9.6 × 10^-19
λ= 2.1 × 10^-7 m
For 4.0 eV
4.0 × 1.6 × 10^-19 = 6.4 × 10^-19 J
E= hc/λ
λ= hc/E
λ= 6.6 × 10^-34 × 3 × 10^8/6.4 × 10^-19
λ= 3.1 × 10^- 7 m
Answer:
the kinetic energy lost due to friction is 22.5 J
Explanation:
Given;
mass of the block, m = 0.2 kg
initial velocity of the block, u = 25 m/s
final velocity of the block, v = 20 m/s
The kinetic energy lost due to friction is calculated as;
Therefore, the kinetic energy lost due to friction is 22.5 J