Answer:
Density of copper = 8.9 g/cm³
The density of liquid mercury is 13.6 g/cm³ which means mercury is denser than copper so copper will float on liquid mercury.
Explanation:
Given data:
weight of copper metal = 1896 g
Dimensions of block = 8.4 cm, 5.5 cm, 4.6 cm
Density of copper = ?
Will it float to the liquid mercury = ?
Solution:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
volume of coper metal = 8.4 cm × 5.5 cm × 4.6 cm
volume of coper metal =212.52 cm³
d = 1896 g/ 212.52 cm³
d = 8.9 g/cm³
The density of liquid mercury is 13.6 g/cm³ which means mercury is denser than copper so copper will float on liquid mercury.
Answer:
Product formed is octan-3-one.
Explanation:
is a Gilman reagent. General formula of Gilman reagent is .
Where R is alkyl group or aryl group.
Gilman reagents react with the organo halides to replace halides with alkyl group or aryl group and this reaction is known as Corey–House synthesis.
When hexanoyl chloride is treated with , the chloride group of the hexanoyl chloride is substituted with the ethyl group of the to form octan-3-one with the removal of EtCu and LiCl.
Answer:
habitat destruction, overexploitation, climate change, nitrogen pollution, and invasive species.
Explanation:
Main Modern Causes of Extinction:
habitat destruction - the process by which a natural habitat becomes incapable of supporting its native species.
overexploitation - harvesting a renewable resource to the point of diminishing returns.
climate change - includes both global warmings driven by human emissions of greenhouse gases and the resulting large-scale shifts in weather patterns.
nitrogen pollution - a form of water pollution, refers to contamination by excessive inputs of nutrients.
invasive species - an introduced organism that negatively alters its new environment.
Answer:
A. Robots go places humans are unable to go.
3 moles of oxygen will react with 1 mole of ethylene. Convert 12.9 L of oxygen to x moles of oxygen, then divide by three.