Answer:
1/12
Step-by-step explanation:
There are two dices being rolled. A dice has six faces numbered from one to six. A fair dice means that the probability of each number to appear is equal. Thus the probability of any number showing up is:
P(a number appears on the dice) = how much times the number has been displayed on the dice/number of faces of the dice.
Since all numbers appear once, and there are six sides of a dice. therefore:
P(a number appears on the dice) = 1/6. Thus, P(6 appears on a dice) = 1/6.
As far as the odd numbers are concerned, there are three even numbers and three odd numbers on the dice. So P(odd number appears on the dice) = 3/6 = 1/2.
Assuming that the probabilities of both the dices are independent, we can safely multiply both the probabilities. Thus:
P(first dice lands on a 6 and second dice lands on an odd number) = 1/6 * 1/2 = 1/12.
Thus, the final probability is 1/12!!!
The parent function was moved left one and down five. It also opened up due to the 1/2
Circle graphs or pie charts are used to represent data in percentages or proportions
- 192 voted for Goron
- 288 voted for Smith or Fishman
<h3>People that voted for Goron</h3>
The total number of votes is given as:
Total = 640
The circle chart is not given.
So, we make use of an assumed value
Assume 30% voted for Goron
The number of people would be:
Goron = 30% * 640
Evaluate
Goron = 192
Hence, 192 voted for Goron using the assumed value
<h3>People that voted for Smith or Fishman</h3>
Assume 45% voted for Smith or Fishman
The number of people would be:
Smith or Fishman = 45% * 640
Evaluate
Smith or Fishman = 288
Hence, 288 voted for Smith or Fishman using the assumed value
Read more about circle graphs at:
brainly.com/question/24461724
<span>Our primary counting system is based on binary digits to represent numbers</span>
Assuming that means 1.10^t:
0.10 is for years. To get months divide by 12.
0.10/12 = 0.0083333...
And (1+0.083333...) = 1.0833333. (You will have to multiply t by 12 also to get it in terms of months)
(1.0833333)^12t