R- (-3,-4)
S- (-3,-1)
T- (-1,-4)
Answer:
Step-by-step explanation:
Solve for :
-Use <u>Distributive Property</u>:
-Combine like terms:
-Subtract from :
-Add on both sides :
-Take divide it on both sides of the equation:
Therefore, the value of is .
Answer:
The % of the increase in population from 1980 to 2000 will be 72.8%
Step-by-step explanation:
Let the population in the year of 1980 was x.
If the population from 1980 to 1990 has increased by 20%, then the population in the year 1990 will be .
Now, from 1990 to 2000, the population has again increased by 20%.
So, the population in the year 2000 will be .
Again, from 2000 to 2010, the population has increased by 20%.
Therefore, the population in the year 2010 will be .
Now, the population increased from x to 1.728x between the years 1980 to 2010.
Hence, the % of the increase in population from 1980 to 2000 will be (Answer)
Answer:
120mph.
Step-by-step explanation:
let s = the speed of the private plane
then
(2s+60) = the speed of the commercial airliner
:
Write a time equation; time = dist/speed
300%2Fs = 750%2F%28%282s%2B60%29%29
cross multiply
750s = 300(2s+60)
750s = 600s + 18000
750s - 600s = 18000
150s = 18000
s = 18000/150
s = 120 mph is the speed of the private plane
then
2(120) + 60 = 300 mph is speed of the commercial airliner
:
:
Check this find the actual time for each
300/120 = 2.5 hrs
750/300 = 2.5 hrs, confirms our solutions
Find the speed of each aircraft
The ratio of the distances flown is 750:300 = 5:2. Since the times are the same, the ratio of the speeds is 5:2. So let the two speeds be 5x and 2x.
The speed of the airliner in mph is 60 more than twice the speed of the private plane:
5x+=+2%282x%29%2B60
5x+=+4x%2B60
x+=+60
The speeds of the two aircraft are 5x = 300mph and 2x = 120mph.
So first
15 L=xquart
so 1L=1.06Q so
15Q=15 times 1.06=15.9Q
then round up to the nearest tenth which is the place denoted by x
15.x
it is already rounded up so the answer is 15.9Q