Answer:
300 Kilo-meters
Step-by-step explanation:
Since 4 / 5 of a liter runs for 12 kilo-meters and you need to find how much 20 liters would run, you need to find how much a liter can run for.
L is the variable for which how much a liter can run for. Which is what we need to solve.
4 / 5 x L = 12
To isolate L, you need to multiply both sides by 5/4 since multiplying a number by its reciprocal produces one. Note: A reciprocal is a number where the denominator and numerator are switched. Example: 2/3 and 3/2 multiplying it with each other get 6/6 which is 1.
4 / 5 x 5 / 4 x L = 12 x 5 / 4
L = 12 x 5 / 4
L = 60/4
L = 15
Now you know that each liter is worth 15 kilo-meters and you need to find how much 20 liters will run for.
20 x L = Kilo's Ran
20 x 15 = Kilo's Ran
300 = Kilo's Ran
20 Liters will run for 300 Kilo-meters.
I Hope This Helps You :)
60 minutes in 1 hr, 60 seconds in 1 minute....(60 * 60) = 3600 seconds in 1 hr
(1/4) / 36 = x / 3600...1/4 mile to 36 seconds = x miles to 3600 seconds
cross multiply
(36)(x) = (1/4)(3600)
36x = 900
x = 900/36
x = 25 mph <==
Answer:
B.) f(x) = 3(4)x − 1
Step-by-step explanation:
A) f(x) = 12(4)x
B.) f(x) = 3(4)x − 1
C.) f(x) = 4(12)x
D.) f(x) = 4(3)x − 1
Given:
f(x+1) = 4f(x)
f(2)=12
f(2) = 12
f(3) = 4f(2) = 4 * 12 = 48
f(3)=48 and f(2)=12
From f(3)=48 and f(2)=12
r=48/12
=4
r=common ratio
Recall,
f(2)=12=ar
r=4
f(2)=ar=12
a*4=12
a=12/4
a=3
an=ar^(n-1)
For x term
an=3*4(x-1)
B.) f(x) = 3(4)x − 1
Answer:
Step-by-step explanation:
For this case we have the following data:
represent the random sample 1 selected
represent the proportion of success for the sample 1 selected
represent the random sample 2 selected
represent the proportion of success for the sample 2 selected
We know for this case that we can use the normal approximation since for both cases we have:
We have the randomization condition and we assume that the two samples are <10% of the entire population size.
So then we can use the following distribution for the proportions:
For this case we want to find the distribution for the difference of these two proportions and we have this:
So then the dtandard deviation would be given by: