Draw a perpendicular segment from point C to the midpoint of AB. Using the trig sine function sin 80 = x/6 which gives 5.91 for the perpendicular segment. Using the formula A=1/2bh, A= 1/2 x5.91x2sqrt 2 A= 8.4
7 is your answer let me know if you need help with anything else
Is it asking how much money she spent or how much she has left
Answer:
D. 25pi
Step-by-step explanation:
"circumscribed" means the rectangle is inside the circle and just the corners (vertices) of the rectangle are touching the circle. This means the diagonal of the rectangle is the diameter of the circle. See image. If the sides of the rectangle are 6 and 8 then the third side that makes the triangle(half the rectangle) is 10. You can find this using Pythagorean Theorem or Pythagorean triples (shortcut)
6^2 + 8^2 = d^2
36 + 64 = d^2
100 = d^2
d = 10
This is the diameter of the circle. The radius would then be 5.
Area of a circle is:
A = pi•r^2
= pi•5^2
= 25pi
Answer:
y = (6ln(x) + C)/x
A
is not a solution to the differential equation
x²y' + xy = x²
as required. This is probably due to an error in typing either the differential equation, or the value of y.
When you've checked the correct values, the same procedure is followed in obtaining the desired result.
Step-by-step explanation:
Suppose y = (6ln(x) + C)/x
is a solution to the differential equation
x²y' + xy = x²
Differentiate y with respect to x
y' = (6/x)/x - (6ln(x) + C)/x²
= (6 - 6ln(x) - C)/x²
Using this value in the differential equation,
x²(6 - 6ln(x) - C)/x² + x(6ln(x) + C)/x
= 6 - 6ln(x) - C + 6ln(x) + C
= 6