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MaRussiya [10]
2 years ago
6

Given the unbalanced equation: Li + N2 -> Li3N When the equation is

Chemistry
1 answer:
olya-2409 [2.1K]2 years ago
5 0

Answer:

D) 6

Explanation:

The balanced equation would be:

6Li + N2 -> 2Li3N

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28 is great.......... it should be snSwer

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Alright, now you actually have an aqueous solution of your salt! Though perhaps not all of the salt has dissolved yet, but we'll
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If not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

<h3>What is concentration?</h3>

The concentration is the amount of substance that is present in solution. We know that we can not measure the concentration unless all of the solute have been dissolved in the solution.

Thus, if not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

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1 year ago
Which compound has the highest percent com­position by mass of strontium?
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3 years ago
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Generic Formula &amp; Molecular Geometry of o3
ella [17]

Answer:

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Explanation:

5 0
2 years ago
Perform the calculation and report the answer using the proper number of significant figures. Make sure the answer is rounded co
shusha [124]

This question is an incomplete question, here is a complete question.

Perform the following calculation. Report the answer using the proper number of significant figures.

\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}=?

Answer : The answer will be, 3.46J/g.K

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

The given expression is,

\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}

\frac{1.012\times 10^{-3}J}{(0.025456g)\times (0.0115)K}

\Rightarrow 3.4569J/g.K

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2 years ago
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