Answer : To find the molar mass of unknown gas we need to solve the equation of rate of diffusion and molecular weight of the gases, which is as follows;
here the mol wt of gas B is not known so we take it as '<em>x'
</em>on solving we get 7 X
/ 4.9 X
<em>
</em>mol. wt of unknown gas =
20.0 g
Answer: C10H8 + 12O2 ----> 10CO2 + 4H2O
Explanation:
To balance this, we have to make sure that the same number of atoms exist at both sides (Conservation of energy)
Note:The reaction is exothermic, giving off heat energy.
Left hand side: C= 10,
H=8,
O= 2×12=24
Right hand side: C= 10×1=10,
H= 4×2=8,
O=10×2=20 (for 10CO2) and 4×1=4 (All equal to 24)
With the above analysis, it is clear that numbers had to be added to molecules to get an equal number of atoms for both sides.
Answer:
The pH decreases very quickly, more quickly than earlier or later in the titration.
I think because SA-SB titration have the straight line where the equivalence point is where pH change is very steep and fast. Also pH is gonna decrease because after equivalence point you have more acid then base.
Explanation:
Answer:
D. Cleavage. Cleavage tends to be the testing of being scratched. Therefore the answer should be Cleavage
Answer:
Five peaks
Explanation:
GaAs would show two peaks:
Ga-69 + As-75 = 144
Ga-71 + As-75 = 146
Their intensities are in the ratio 60 : 40 = 100:67.
Ga₂S₂ would show three peaks:
Ga-69 + Ga-69 + 2As-75 = (Ga-69)₂(As-75)₂ = 288
Ga-69 + Ga-71 + 2As-75 = (Ga-69)(Ga-71(As-75)₂ = 290
Ga-71 + Ga-71 + 2As-75 = (Ga-71)₂(As-75)₂ = 292
Their relative intensities are in the ratio
(60 + 40)² = 60² : 2×60×40 : 40² = 3600 : 4800 : 1600 = 75 : 100 : 33
A spectrum of a mixture of GaAs and Ga₂As₂ would show five peaks:
Two at m/e 144 and 146 with intensity ratios 100: 67 and
Three at m/e 288, 290, and 292 with intensity ratios 75:100 :33.
We cannot predict the absolute sizes of the peaks because we do not know the relative amounts of GaAs and GaAs₂.