Given :
In the early spring, the trout at Big Blue Lake swim at a depth of 30 feet below sea level.
When the lake warms up in the summer, the trout swim 20 feet deeper than that , d = 20 feet .
To Find :
At what position relative to sea level do the trout swim in the summer.
Solution :
Depth in spring from surface , .
Let , depth in summer is D .
Now , depth in summer relative to sea-level is :
Therefore , trout swim 50 feet deep below the sea level in the summer .
Hence , this is the required solution .
Answer:
D.
Step-by-step explanation:
According to the Exterior Angle Theorem, the exterior angle is equal to the sum of the interior angles opposite from the exterior angle. In other words:
Solve for <em>x</em>. Therefore:
Our answer is D.
2,3,5,8,13,19 they are all going up the first one goes up by one,then, 2, 3.. etc
The slope/y-int form would be y=9/2x+2 you have to move the x value and whole number(y-int) to the other side which would make them negative and then divide by the -2 and there you go.
The answer, is CD. The 3rd one