5 consecutive even integers: n, n+2,n+4,n+6,n+8
n+(n+2)+(n+4)+(n+6)+(n+8)=1310
combine like terms
5n+20 = 1310
subtract 20 from each side
5n = 1290
divide by 5
n=258
n+2 = 260
n+4=262
n+6=264
n+8=266
Answer: 258,260,262,264,266
Answer:
x = -5
Step-by-step explanation:
We can use the below formula to find the line of symmetry.
( x - a )² + b
Here,
line of symmetry = +a
Vertex = +b
And now let us take a look at the given equation.
y = x² + 10x + 22
To find the line of symmetry from the given equation we have to make the given equation as the given formula.
Let us use the completing square method for that.
y = x² + 10x + 22
<em>Put zero instead of y.</em>
x² + 10x + 22 = 0
x² + 10x = -22
x² + 10x + 25 = -22 + 25
( x + 5 )² = 3
( x + 5 )² -3 = 0
Therefore,
line of symmetry of the line is = -5
∴ x = -5
(6x-18)(x+4)/(3x-9)=6(x-3)(x+4)/3(x-3)=2(x+4)=2x+8
She had 47$.
She then writes a check for $55 and give it away.
47-55=-8.
Her balance will be $-8