Answer:
The probability that cards # 1, # 2, and # 3 are still in order on the top of the stack is 0.045%.
Step-by-step explanation:
Since a politician is about to give a campaign speech and is holding a stack of thirteen cue cards, of which the first 3 are the most important, and just before the speech, she drops all of the cards and picks them up in a random order, to determine what is the probability that cards # 1, # 2, and # 3 are still in order on the top of the stack, the following calculation must be performed:
1/13 x 1/13 x 1/13 = X
0.076 x 0.076 x 0.076 = X
0.00045 = X
0.00045 x 100 = 0.045
Therefore, the probability that cards # 1, # 2, and # 3 are still in order on the top of the stack is 0.045%.
