Answer: The angle between the carbon-chlorine bonds in phosgene will be 120°
Explanation: Formula used to calculate the hybridization:
where,
V = number of valence electrons present in central atom i.e. carbon = 4
N = number of monovalent atoms bonded to central atom = 2
C = charge of cation = 0
A = charge of anion = 0
For
The number of electron pairs are 3 which means that the hybridization will be and the electronic geometry of the given molecule will be trigonal planar.
The bond angle in this electronic geometry is 120°
The structure of phosgene is attached below.
Answer:
The answer to your question is: letter B
Explanation:
The information given is showing us three kinds of carbons and their respective number of protons and neutrons. Now, let's analize the options given:
A.)Carbon Bond Types This option is about trhe kind of bonds carbon is able to form like single, double or triple and is different from the information descrive above. So ,this option is incorrect.
B.)Carbon Isotopes is option is about the carbon atoms that have the same number of protons and different amount of neutrons exactly as it is describe above, to this option is correct.
C.)The Carbon Cycle
this option is about how carbon goes from one kind of matter to another and is completely different to the description given above, so this option is incorrect.
D.)Chemical Reactions this option is about reactants that after a process give products they could be from carbon -12, carbon-13 or carbon-14 and other elements, so this option is different from the description given above.
Answer:
Sedimentary rocks are formed when sediment is deposited out of air, ice, wind, gravity, or water flows carrying the particles in suspension. This sediment is often formed when weathering and erosion break down a rock into loose material in a source area.
Explanation:
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Answer:
The final molarity of nitrate anion in the solution is 0.258 M.
Explanation:
Mass of barium nitrate 1.73 g
Moles of barium nitrate =
1 mole of barium nitrate gives 2 moles of nitrate ions,then 0.00662 mol of barium nitrate will give :
of nitrate ions
moles of nitrate ion added to the solution = 0.01324 mol
Molarity of the barium nitrate solution = 63.0 mM = 0.063 M
1 mM = 0.001 M
Volume of barium nitrate solution = 100 mL = 0.100 L
1 m L = 0.001 mL
Moles of barium nitrate in the solution = n
Moles of nitrate ion in solution = 2 0.0063 × mol = 0.0126 mol
Total moles og nitrate ions = 0.01324 mol + 0.0126 mol = 0.02584 mol
Final molarity of nitrate anion in the solution.:
The final molarity of nitrate anion in the solution is 0.258 M.