Question

How do i solve for x. e(x+c)÷b=2

Answer 1

Answer:

$x = \frac{2b}{e} - c$

Step-by-step explanation:

e(x + c) ÷ b = 2   Do orders of operation

(ex + ec) ÷ b = 2  Distribute e into x and c

$\frac{ex + ec}{b} = 2$  Divide ex + ec by b

$(b)\frac{ex + ec}{b} = 2(b)$ Multiply both sides by b to cancel it out

ex + ec = 2b  Subtract ec from both sides to get ex alone

     - ec  - ec

ex = 2b - ec  Now you have ex alone

$\frac{ex}{e} = \frac{2b - ec}{e}$  Divide both sides by e to x alone

$x = \frac{2b}{e} - c$