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3 years ago

15-b=12 I need helpplz

Mathematics

2 answers:

astraxan [27]3 years ago

4 0

Answer:

b = 3

Step-by-step explanation:

15 - b = 12

-b = -3

b = 3

<em><u>Hope this helped! Have a nice day! Plz mark as brainliest!!!</u></em>

<em><u>-XxDeathshotxX</u></em>

timofeeve [1]3 years ago

3 0

Answer:

b=3

Step-by-step explanation:

15-b=12

-b=12-15

-b=-3 divide both sides by -1

b=3

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If a and b are two angles in standard position in Quadrant I, find cos(a+b) for the given function values. sin a=15/17and cos b=

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The value of $cos(a+b)$ for the angles $a$ and $b$ in standard position in the first quadrant is $-\frac{36}{85}$

We need to find the value of $cos(a+b)$ . To proceed, we need to use the compound angle formula

<h3>Cosine of a sum of two angles</h3>

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We are given

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To find $cos(a)$ , note that

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substituting $\frac{15}{17}$ for $sin(a)$ in the identity, we get

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We can now make use of the formula

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$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)\\\\=\dfrac{8}{17}\cdot\dfrac{3}{5}-\dfrac{15}{17}\cdot\dfrac{4}{5}=-\dfrac{36}{85}$

Learn more about sine and cosine of compound angles here brainly.com/question/24305408

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tell what you get

You're welcome

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15-b=12 I need helpplz​

15-b=12 I need helpplz